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2113005543 = 31164030471
BaseRepresentation
bin111110111110001…
…1110011111100111
312110020222210200120
41331330132133213
513311412134133
6545401013023
7103235152005
oct17574363747
95406883616
102113005543
11994811380
124ab784173
132789c274c
141608b3a75
15c5785ab3
hex7df1e7e7

2113005543 has 8 divisors (see below), whose sum is σ = 3073462656. Its totient is φ = 1280609400.

The previous prime is 2113005541. The next prime is 2113005571. The reversal of 2113005543 is 3455003112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2113005543 - 21 = 2113005541 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2113005541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 32015203 + ... + 32015268.

It is an arithmetic number, because the mean of its divisors is an integer number (384182832).

Almost surely, 22113005543 is an apocalyptic number.

2113005543 is a deficient number, since it is larger than the sum of its proper divisors (960457113).

2113005543 is a wasteful number, since it uses less digits than its factorization.

2113005543 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 64030485.

The product of its (nonzero) digits is 1800, while the sum is 24.

The square root of 2113005543 is about 45967.4400309610. The cubic root of 2113005543 is about 1283.2173179807.

Adding to 2113005543 its reverse (3455003112), we get a palindrome (5568008655).

The spelling of 2113005543 in words is "two billion, one hundred thirteen million, five thousand, five hundred forty-three".

Divisors: 1 3 11 33 64030471 192091413 704335181 2113005543