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211310000000000 = 2105101117113
BaseRepresentation
bin110000000010111101110001…
…011111001100110000000000
31000201012001001012222101202022
4300002331301133030300000
5210144100340000000000
62025230250204541012
762336433534155456
oct6002756137146000
91021161035871668
10211310000000000
116136a082183570
121b849363551768
1390ba5a81cbca5
143a2765c4609d6
1519669d0cb5585
hexc02f717ccc00

211310000000000 has 968 divisors, whose sum is σ = 615299401461168. Its totient is φ = 71680000000000.

The previous prime is 211309999999991. The next prime is 211310000000009. The reversal of 211310000000000 is 13112.

It is an interprime number because it is at equal distance from previous prime (211309999999991) and next prime (211310000000009).

It is a super-2 number, since 2×2113100000000002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (8).

It is not an unprimeable number, because it can be changed into a prime (211310000000009) by changing a digit.

It is a polite number, since it can be written in 87 ways as a sum of consecutive naturals, for example, 1869999999944 + ... + 1870000000056.

Almost surely, 2211310000000000 is an apocalyptic number.

211310000000000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 211310000000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (307649700730584).

211310000000000 is an abundant number, since it is smaller than the sum of its proper divisors (403989401461168).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

211310000000000 is an frugal number, since it uses more digits than its factorization.

211310000000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 211 (or 148 counting only the distinct ones).

The product of its (nonzero) digits is 6, while the sum is 8.

Adding to 211310000000000 its reverse (13112), we get a palindrome (211310000013112).

The spelling of 211310000000000 in words is "two hundred eleven trillion, three hundred ten billion", and thus it is an aban number.