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211311032021 = 434914210047
BaseRepresentation
bin1100010011001100011…
…1100111011011010101
3202012102121222122110022
43010303013213123111
511430231111011041
6241024104434525
721160325064515
oct3046307473325
9665377878408
10211311032021
1181686628a51
1234b53778a45
1316c07807b2b
14a3283d7845
15576b4a124b
hex31331e76d5

211311032021 has 4 divisors (see below), whose sum is σ = 216225242112. Its totient is φ = 206396821932.

The previous prime is 211311032017. The next prime is 211311032039. The reversal of 211311032021 is 120230113112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 211311032021 - 22 = 211311032017 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211311032011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2457104981 + ... + 2457105066.

It is an arithmetic number, because the mean of its divisors is an integer number (54056310528).

Almost surely, 2211311032021 is an apocalyptic number.

It is an amenable number.

211311032021 is a deficient number, since it is larger than the sum of its proper divisors (4914210091).

211311032021 is an equidigital number, since it uses as much as digits as its factorization.

211311032021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4914210090.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 211311032021 its reverse (120230113112), we get a palindrome (331541145133).

The spelling of 211311032021 in words is "two hundred eleven billion, three hundred eleven million, thirty-two thousand, twenty-one".

Divisors: 1 43 4914210047 211311032021