Base | Representation |
---|---|
bin | 1100010011001100110… |
… | …0000100101001101101 |
3 | 202012102201012000000221 |
4 | 3010303030010221231 |
5 | 11430231410402201 |
6 | 241024145451341 |
7 | 21160341031546 |
oct | 3046314045155 |
9 | 665381160027 |
10 | 211312200301 |
11 | 81687256774 |
12 | 34b54040b51 |
13 | 16c07b26817 |
14 | a32861d4cd |
15 | 576b6324a1 |
hex | 3133304a6d |
211312200301 has 4 divisors (see below), whose sum is σ = 211753353600. Its totient is φ = 210871047004.
The previous prime is 211312200277. The next prime is 211312200347. The reversal of 211312200301 is 103002213112.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 211312200301 - 217 = 211312069229 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (211312200391) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 220575931 + ... + 220576888.
It is an arithmetic number, because the mean of its divisors is an integer number (52938338400).
Almost surely, 2211312200301 is an apocalyptic number.
It is an amenable number.
211312200301 is a deficient number, since it is larger than the sum of its proper divisors (441153299).
211312200301 is an equidigital number, since it uses as much as digits as its factorization.
211312200301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 441153298.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 211312200301 its reverse (103002213112), we get a palindrome (314314413413).
The spelling of 211312200301 in words is "two hundred eleven billion, three hundred twelve million, two hundred thousand, three hundred one".
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