Base | Representation |
---|---|
bin | 1001100111000000010110… |
… | …11101010110110000111011 |
3 | 2202211010220210010211122111 |
4 | 10303200023131112300323 |
5 | 10232204132410403430 |
6 | 112535351234233151 |
7 | 4310460365523304 |
oct | 463401335266073 |
9 | 82733823124574 |
10 | 21131431341115 |
11 | 68078761078a7 |
12 | 24534b57257b7 |
13 | ba38bab570b4 |
14 | 530aa3cbd7ab |
15 | 269a24e46c2a |
hex | 13380b756c3b |
21131431341115 has 4 divisors (see below), whose sum is σ = 25357717609344. Its totient is φ = 16905145072888.
The previous prime is 21131431341103. The next prime is 21131431341121. The reversal of 21131431341115 is 51114313413112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 21131431341115 - 221 = 21131429243963 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2113143134107 + ... + 2113143134116.
It is an arithmetic number, because the mean of its divisors is an integer number (6339429402336).
Almost surely, 221131431341115 is an apocalyptic number.
21131431341115 is a deficient number, since it is larger than the sum of its proper divisors (4226286268229).
21131431341115 is an equidigital number, since it uses as much as digits as its factorization.
21131431341115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4226286268228.
The product of its digits is 4320, while the sum is 31.
Adding to 21131431341115 its reverse (51114313413112), we get a palindrome (72245744754227).
The spelling of 21131431341115 in words is "twenty-one trillion, one hundred thirty-one billion, four hundred thirty-one million, three hundred forty-one thousand, one hundred fifteen".
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