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21132104111 = 125831679417
BaseRepresentation
bin10011101011100100…
…100101000110101111
32000112201210010010122
4103223210211012233
5321234304312421
613412530155155
71345446630656
oct235344450657
960481703118
1021132104111
118a64581658
124119122abb
131cba0b9221
1410467c019d
1583a3442ab
hex4eb9251af

21132104111 has 4 divisors (see below), whose sum is σ = 21133796112. Its totient is φ = 21130412112.

The previous prime is 21132104101. The next prime is 21132104117. The reversal of 21132104111 is 11140123112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21132104111 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 21132104111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21132104117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 827126 + ... + 852291.

It is an arithmetic number, because the mean of its divisors is an integer number (5283449028).

Almost surely, 221132104111 is an apocalyptic number.

21132104111 is a deficient number, since it is larger than the sum of its proper divisors (1692001).

21132104111 is a wasteful number, since it uses less digits than its factorization.

21132104111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1692000.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 21132104111 its reverse (11140123112), we get a palindrome (32272227223).

The spelling of 21132104111 in words is "twenty-one billion, one hundred thirty-two million, one hundred four thousand, one hundred eleven".

Divisors: 1 12583 1679417 21132104111