Base | Representation |
---|---|
bin | 10011101011100100… |
… | …100101000110110101 |
3 | 2000112201210010010212 |
4 | 103223210211012311 |
5 | 321234304312432 |
6 | 13412530155205 |
7 | 1345446630665 |
oct | 235344450665 |
9 | 60481703125 |
10 | 21132104117 |
11 | 8a64581663 |
12 | 4119122b05 |
13 | 1cba0b9227 |
14 | 10467c01a5 |
15 | 83a3442b2 |
hex | 4eb9251b5 |
21132104117 has 2 divisors, whose sum is σ = 21132104118. Its totient is φ = 21132104116.
The previous prime is 21132104101. The next prime is 21132104129. The reversal of 21132104117 is 71140123112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 21078974596 + 53129521 = 145186^2 + 7289^2 .
It is a cyclic number.
It is not a de Polignac number, because 21132104117 - 24 = 21132104101 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21132104092 and 21132104101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21132104717) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10566052058 + 10566052059.
It is an arithmetic number, because the mean of its divisors is an integer number (10566052059).
Almost surely, 221132104117 is an apocalyptic number.
It is an amenable number.
21132104117 is a deficient number, since it is larger than the sum of its proper divisors (1).
21132104117 is an equidigital number, since it uses as much as digits as its factorization.
21132104117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 336, while the sum is 23.
Adding to 21132104117 its reverse (71140123112), we get a palindrome (92272227229).
The spelling of 21132104117 in words is "twenty-one billion, one hundred thirty-two million, one hundred four thousand, one hundred seventeen".
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