Base | Representation |
---|---|
bin | 10011101011100111… |
… | …111111110111010111 |
3 | 2000112210110122021022 |
4 | 103223213333313113 |
5 | 321240022001101 |
6 | 13413001311355 |
7 | 1345460352224 |
oct | 235347776727 |
9 | 60483418238 |
10 | 21133000151 |
11 | 8a6503388a |
12 | 411949555b |
13 | 1cba341023 |
14 | 104697494b |
15 | 83a46ea1b |
hex | 4eb9ffdd7 |
21133000151 has 2 divisors, whose sum is σ = 21133000152. Its totient is φ = 21133000150.
The previous prime is 21133000129. The next prime is 21133000153. The reversal of 21133000151 is 15100033112.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21133000151 is a prime.
It is a Sophie Germain prime.
Together with 21133000153, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21133000153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10566500075 + 10566500076.
It is an arithmetic number, because the mean of its divisors is an integer number (10566500076).
Almost surely, 221133000151 is an apocalyptic number.
21133000151 is a deficient number, since it is larger than the sum of its proper divisors (1).
21133000151 is an equidigital number, since it uses as much as digits as its factorization.
21133000151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90, while the sum is 17.
Adding to 21133000151 its reverse (15100033112), we get a palindrome (36233033263).
The spelling of 21133000151 in words is "twenty-one billion, one hundred thirty-three million, one hundred fifty-one", and thus it is an aban number.
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