Base | Representation |
---|---|
bin | 110000000011011010000110… |
… | …001111111110110011011000 |
3 | 1000201021221112202121010100101 |
4 | 300003122012033332303120 |
5 | 210200100131223301240 |
6 | 2025252240115145144 |
7 | 62341561311242254 |
oct | 6003320617766330 |
9 | 1021257482533311 |
10 | 211340413103320 |
11 | 61380a696221a6 |
12 | 1b8532308a51b4 |
13 | 90c0414042907 |
14 | 3a28d056c1264 |
15 | 19676b0ce039a |
hex | c036863fecd8 |
211340413103320 has 32 divisors (see below), whose sum is σ = 483311272594320. Its totient is φ = 83150326465920.
The previous prime is 211340413103297. The next prime is 211340413103359. The reversal of 211340413103320 is 23301314043112.
211340413103320 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 43307459262 + ... + 43307464141.
Almost surely, 2211340413103320 is an apocalyptic number.
211340413103320 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
211340413103320 is an abundant number, since it is smaller than the sum of its proper divisors (271970859491000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
211340413103320 is a wasteful number, since it uses less digits than its factorization.
211340413103320 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 86614923475 (or 86614923471 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 211340413103320 its reverse (23301314043112), we get a palindrome (234641727146432).
The spelling of 211340413103320 in words is "two hundred eleven trillion, three hundred forty billion, four hundred thirteen million, one hundred three thousand, three hundred twenty".
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