Base | Representation |
---|---|
bin | 1100010011100010101… |
… | …0010001010000101111 |
3 | 202012200002221000202212 |
4 | 3010320222101100233 |
5 | 11430423411033401 |
6 | 241041225241035 |
7 | 21162534241163 |
oct | 3047052212057 |
9 | 665602830685 |
10 | 211404002351 |
11 | 81724058a33 |
12 | 34b7a93317b |
13 | 16c20b59a69 |
14 | a3368b8ca3 |
15 | 5774717dbb |
hex | 3138a9142f |
211404002351 has 2 divisors, whose sum is σ = 211404002352. Its totient is φ = 211404002350.
The previous prime is 211404002287. The next prime is 211404002393. The reversal of 211404002351 is 153200404112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211404002351 - 26 = 211404002287 is a prime.
It is a super-2 number, since 2×2114040023512 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211404001351) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105702001175 + 105702001176.
It is an arithmetic number, because the mean of its divisors is an integer number (105702001176).
Almost surely, 2211404002351 is an apocalyptic number.
211404002351 is a deficient number, since it is larger than the sum of its proper divisors (1).
211404002351 is an equidigital number, since it uses as much as digits as its factorization.
211404002351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 960, while the sum is 23.
Adding to 211404002351 its reverse (153200404112), we get a palindrome (364604406463).
The spelling of 211404002351 in words is "two hundred eleven billion, four hundred four million, two thousand, three hundred fifty-one".
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