Base | Representation |
---|---|
bin | 1100010011100110100… |
… | …0001100001000111101 |
3 | 202012201020110200211012 |
4 | 3010321220030020331 |
5 | 11430442034444201 |
6 | 241043005205005 |
7 | 21163122224513 |
oct | 3047150141075 |
9 | 665636420735 |
10 | 211420234301 |
11 | 81732235271 |
12 | 34b84260765 |
13 | 16c24321073 |
14 | a338b024b3 |
15 | 5775d725bb |
hex | 3139a0c23d |
211420234301 has 2 divisors, whose sum is σ = 211420234302. Its totient is φ = 211420234300.
The previous prime is 211420234297. The next prime is 211420234343. The reversal of 211420234301 is 103432024112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 127842002500 + 83578231801 = 357550^2 + 289099^2 .
It is a cyclic number.
It is not a de Polignac number, because 211420234301 - 22 = 211420234297 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211420234381) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105710117150 + 105710117151.
It is an arithmetic number, because the mean of its divisors is an integer number (105710117151).
Almost surely, 2211420234301 is an apocalyptic number.
It is an amenable number.
211420234301 is a deficient number, since it is larger than the sum of its proper divisors (1).
211420234301 is an equidigital number, since it uses as much as digits as its factorization.
211420234301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 211420234301 its reverse (103432024112), we get a palindrome (314852258413).
The spelling of 211420234301 in words is "two hundred eleven billion, four hundred twenty million, two hundred thirty-four thousand, three hundred one".
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