21142101300 has 144 divisors (see below), whose sum is σ = 62911598400. Its totient is φ = 5479654400.

The previous prime is 21142101269. The next prime is 21142101307. The reversal of 21142101300 is 310124112.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 21142101300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21142101307) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1568590 + ... + 1582010.

It is an arithmetic number, because the mean of its divisors is an integer number (436886100).

Almost surely, 2^21142101300 is an apocalyptic number.

21142101300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 21142101300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (31455799200).

21142101300 is an abundant number, since it is smaller than the sum of its proper divisors (41769497100).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

21142101300 is a wasteful number, since it uses less digits than its factorization.

21142101300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13586 (or 13579 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 21142101300 its reverse (310124112), we get a palindrome (21452225412).

The spelling of 21142101300 in words is "twenty-one billion, one hundred forty-two million, one hundred one thousand, three hundred".