Base | Representation |
---|---|
bin | 1100010011100110101… |
… | …1001110011100111111 |
3 | 202012201021222010121012 |
4 | 3010321223032130333 |
5 | 11430442240431312 |
6 | 241043034225435 |
7 | 21163132051112 |
oct | 3047153163477 |
9 | 665637863535 |
10 | 211421030207 |
11 | 81732729242 |
12 | 34b8458527b |
13 | 16c2453c40a |
14 | a338c6c579 |
15 | 5775e7d322 |
hex | 3139ace73f |
211421030207 has 2 divisors, whose sum is σ = 211421030208. Its totient is φ = 211421030206.
The previous prime is 211421030201. The next prime is 211421030209. The reversal of 211421030207 is 702030124112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211421030207 - 212 = 211421026111 is a prime.
Together with 211421030209, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211421030201) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105710515103 + 105710515104.
It is an arithmetic number, because the mean of its divisors is an integer number (105710515104).
Almost surely, 2211421030207 is an apocalyptic number.
211421030207 is a deficient number, since it is larger than the sum of its proper divisors (1).
211421030207 is an equidigital number, since it uses as much as digits as its factorization.
211421030207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 672, while the sum is 23.
Adding to 211421030207 its reverse (702030124112), we get a palindrome (913451154319).
The spelling of 211421030207 in words is "two hundred eleven billion, four hundred twenty-one million, thirty thousand, two hundred seven".
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