211447384151 has 2 divisors, whose sum is σ = 211447384152. Its totient is φ = 211447384150.

The previous prime is 211447384037. The next prime is 211447384153. The reversal of 211447384151 is 151483744112.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-211447384151 is a prime.

Together with 211447384153, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 211447384099 and 211447384108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211447384153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105723692075 + 105723692076.

It is an arithmetic number, because the mean of its divisors is an integer number (105723692076).

Almost surely, 2^211447384151 is an apocalyptic number.

211447384151 is a deficient number, since it is larger than the sum of its proper divisors (1).

211447384151 is an equidigital number, since it uses as much as digits as its factorization.

211447384151 is an evil number, because the sum of its binary digits is even.

The product of its digits is 107520, while the sum is 41.

The spelling of 211447384151 in words is "two hundred eleven billion, four hundred forty-seven million, three hundred eighty-four thousand, one hundred fifty-one".