Base | Representation |
---|---|
bin | 11110110001011001111… |
… | …101000110111100111001 |
3 | 21111011020102020202020200 |
4 | 132301121331012330321 |
5 | 234121232033213423 |
6 | 4255240554112413 |
7 | 305530402533651 |
oct | 36613175067471 |
9 | 7434212222220 |
10 | 2114633101113 |
11 | 7458a1291385 |
12 | 2a19b641b709 |
13 | 12454189ac10 |
14 | 744c5109361 |
15 | 3a016c05d43 |
hex | 1ec59f46f39 |
2114633101113 has 72 divisors (see below), whose sum is σ = 3409155743448. Its totient is φ = 1255559768064.
The previous prime is 2114633101073. The next prime is 2114633101151. The reversal of 2114633101113 is 3111013364112.
2114633101113 is a `hidden beast` number, since 2 + 1 + 1 + 4 + 633 + 1 + 0 + 11 + 13 = 666.
It can be written as a sum of positive squares in 12 ways, for example, as 235354027689 + 1879279073424 = 485133^2 + 1370868^2 .
It is not a de Polignac number, because 2114633101113 - 28 = 2114633100857 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2114633101313) by changing a digit.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 157133281 + ... + 157146737.
Almost surely, 22114633101113 is an apocalyptic number.
It is an amenable number.
2114633101113 is a deficient number, since it is larger than the sum of its proper divisors (1294522642335).
2114633101113 is a wasteful number, since it uses less digits than its factorization.
2114633101113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15131 (or 15099 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 27.
Adding to 2114633101113 its reverse (3111013364112), we get a palindrome (5225646465225).
The spelling of 2114633101113 in words is "two trillion, one hundred fourteen billion, six hundred thirty-three million, one hundred one thousand, one hundred thirteen".
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