Base | Representation |
---|---|
bin | 10011101101011100… |
… | …010100111110110111 |
3 | 2000121220211221211011 |
4 | 103231130110332313 |
5 | 321320323322401 |
6 | 13420011053051 |
7 | 1346310512425 |
oct | 235534247667 |
9 | 60556757734 |
10 | 21163495351 |
11 | 8a80272329 |
12 | 4127741187 |
13 | 1cc375a51b |
14 | 104aa32115 |
15 | 83ce95451 |
hex | 4ed714fb7 |
21163495351 has 2 divisors, whose sum is σ = 21163495352. Its totient is φ = 21163495350.
The previous prime is 21163495337. The next prime is 21163495391. The reversal of 21163495351 is 15359436112.
It is a happy number.
It is an a-pointer prime, because the next prime (21163495391) can be obtained adding 21163495351 to its sum of digits (40).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21163495351 - 25 = 21163495319 is a prime.
It is a super-2 number, since 2×211634953512 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21163495321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10581747675 + 10581747676.
It is an arithmetic number, because the mean of its divisors is an integer number (10581747676).
Almost surely, 221163495351 is an apocalyptic number.
21163495351 is a deficient number, since it is larger than the sum of its proper divisors (1).
21163495351 is an equidigital number, since it uses as much as digits as its factorization.
21163495351 is an evil number, because the sum of its binary digits is even.
The product of its digits is 97200, while the sum is 40.
The spelling of 21163495351 in words is "twenty-one billion, one hundred sixty-three million, four hundred ninety-five thousand, three hundred fifty-one".
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