Base | Representation |
---|---|
bin | 1100010101110000110… |
… | …0001111111100110001 |
3 | 202021012122121120002001 |
4 | 3011130030033330301 |
5 | 11433134012044213 |
6 | 241220322054001 |
7 | 21213363136354 |
oct | 3053414177461 |
9 | 667178546061 |
10 | 212000112433 |
11 | 819aa59a29a |
12 | 351064aa301 |
13 | 16cb74c2c15 |
14 | a391b2c29b |
15 | 57abc181dd |
hex | 315c30ff31 |
212000112433 has 8 divisors (see below), whose sum is σ = 227312110080. Its totient is φ = 197003826240.
The previous prime is 212000112421. The next prime is 212000112449. The reversal of 212000112433 is 334211000212.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 212000112433 - 237 = 74561158961 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 212000112433.
It is not an unprimeable number, because it can be changed into a prime (212000112403) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 78926473 + ... + 78929158.
It is an arithmetic number, because the mean of its divisors is an integer number (28414013760).
Almost surely, 2212000112433 is an apocalyptic number.
It is an amenable number.
212000112433 is a deficient number, since it is larger than the sum of its proper divisors (15311997647).
212000112433 is a wasteful number, since it uses less digits than its factorization.
212000112433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 157855727.
The product of its (nonzero) digits is 288, while the sum is 19.
Adding to 212000112433 its reverse (334211000212), we get a palindrome (546211112645).
The spelling of 212000112433 in words is "two hundred twelve billion, one hundred twelve thousand, four hundred thirty-three".
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