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212012012000093 is a prime number
BaseRepresentation
bin110000001101001011100100…
…101010011101001101011101
31000210200011001122101222202012
4300031023210222131031131
5210242101100033000333
62030524550154241005
762441235204543464
oct6015134452351535
91023604048358665
10212012012000093
116160a8756a5658
121b941421a26165
13913b854455316
143a4d616a659db
151979dbb800e48
hexc0d2e4a9d35d

212012012000093 has 2 divisors, whose sum is σ = 212012012000094. Its totient is φ = 212012012000092.

The previous prime is 212012012000069. The next prime is 212012012000119. The reversal of 212012012000093 is 390000210210212.

It is a happy number.

212012012000093 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 204930734421604 + 7081277578489 = 14315402^2 + 2661067^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-212012012000093 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (212012012050093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106006006000046 + 106006006000047.

It is an arithmetic number, because the mean of its divisors is an integer number (106006006000047).

Almost surely, 2212012012000093 is an apocalyptic number.

It is an amenable number.

212012012000093 is a deficient number, since it is larger than the sum of its proper divisors (1).

212012012000093 is an equidigital number, since it uses as much as digits as its factorization.

212012012000093 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 23.

The spelling of 212012012000093 in words is "two hundred twelve trillion, twelve billion, twelve million, ninety-three", and thus it is an aban number.