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21201220031 is a prime number
BaseRepresentation
bin10011101111101100…
…001111000110111111
32000201112211120100112
4103233230033012333
5321410003020111
613423435420235
71350246253055
oct235754170677
960645746315
1021201220031
118a9a599452
1241382b467b
131ccb508514
141051a521d5
15841447e8b
hex4efb0f1bf

21201220031 has 2 divisors, whose sum is σ = 21201220032. Its totient is φ = 21201220030.

The previous prime is 21201219997. The next prime is 21201220049. The reversal of 21201220031 is 13002210212.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 21201220031 - 210 = 21201219007 is a prime.

It is a super-2 number, since 2×212012200312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21201219988 and 21201220015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21201220231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10600610015 + 10600610016.

It is an arithmetic number, because the mean of its divisors is an integer number (10600610016).

Almost surely, 221201220031 is an apocalyptic number.

21201220031 is a deficient number, since it is larger than the sum of its proper divisors (1).

21201220031 is an equidigital number, since it uses as much as digits as its factorization.

21201220031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 21201220031 its reverse (13002210212), we get a palindrome (34203430243).

The spelling of 21201220031 in words is "twenty-one billion, two hundred one million, two hundred twenty thousand, thirty-one".