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212013415 = 553337951
BaseRepresentation
bin11001010001100…
…01000101100111
3112202221101201201
430220301011213
5413233412130
633012103331
75153040625
oct1450610547
9482841651
10212013415
11a97488a9
125b004b47
1334c02433
142022c515
151392dbca
hexca31167

212013415 has 8 divisors (see below), whose sum is σ = 254495808. Its totient is φ = 169557600.

The previous prime is 212013407. The next prime is 212013421. The reversal of 212013415 is 514310212.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 212013415 - 23 = 212013407 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 212013392 and 212013401.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 22690 + ... + 30640.

It is an arithmetic number, because the mean of its divisors is an integer number (31811976).

Almost surely, 2212013415 is an apocalyptic number.

212013415 is a deficient number, since it is larger than the sum of its proper divisors (42482393).

212013415 is an equidigital number, since it uses as much as digits as its factorization.

212013415 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13289.

The product of its (nonzero) digits is 240, while the sum is 19.

The square root of 212013415 is about 14560.6804442650. The cubic root of 212013415 is about 596.2857725609.

Adding to 212013415 its reverse (514310212), we get a palindrome (726323627).

The spelling of 212013415 in words is "two hundred twelve million, thirteen thousand, four hundred fifteen".

Divisors: 1 5 5333 7951 26665 39755 42402683 212013415