Base | Representation |
---|---|
bin | 1001101001001010001010… |
… | …00100110010011010100111 |
3 | 2210002012212122121012122201 |
4 | 10310211011010302122213 |
5 | 10234412141040021320 |
6 | 113033344301435331 |
7 | 4316016613405540 |
oct | 464450504623247 |
9 | 83065778535581 |
10 | 21205412423335 |
11 | 683618a541968 |
12 | 246590186bb47 |
13 | baa87accb4aa |
14 | 5344c15234c7 |
15 | 26b904ce270a |
hex | 1349451326a7 |
21205412423335 has 64 divisors (see below), whose sum is σ = 29853779945472. Its totient is φ = 14159218484736.
The previous prime is 21205412423257. The next prime is 21205412423353. The reversal of 21205412423335 is 53332421450212.
It is a cyclic number.
It is not a de Polignac number, because 21205412423335 - 225 = 21205378868903 is a prime.
It is a super-3 number, since 3×212054124233353 (a number of 41 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21205412423294 and 21205412423303.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 202237192 + ... + 202342018.
It is an arithmetic number, because the mean of its divisors is an integer number (466465311648).
Almost surely, 221205412423335 is an apocalyptic number.
21205412423335 is a deficient number, since it is larger than the sum of its proper divisors (8648367522137).
21205412423335 is a wasteful number, since it uses less digits than its factorization.
21205412423335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 105712.
The product of its (nonzero) digits is 172800, while the sum is 37.
Adding to 21205412423335 its reverse (53332421450212), we get a palindrome (74537833873547).
The spelling of 21205412423335 in words is "twenty-one trillion, two hundred five billion, four hundred twelve million, four hundred twenty-three thousand, three hundred thirty-five".
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