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212102132455 = 542420426491
BaseRepresentation
bin1100010110001001000…
…1011011001011100111
3202021110202120201020101
43011202101123023213
511433341121214310
6241234404444531
721216042244003
oct3054221331347
9667422521211
10212102132455
1181a52140464
12351346a9747
1317002692cb5
14a3a14c7703
1557b5b6b43a
hex316245b2e7

212102132455 has 4 divisors (see below), whose sum is σ = 254522558952. Its totient is φ = 169681705960.

The previous prime is 212102132449. The next prime is 212102132477. The reversal of 212102132455 is 554231201212.

It is a happy number.

212102132455 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 212102132455 - 215 = 212102099687 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21210213241 + ... + 21210213250.

It is an arithmetic number, because the mean of its divisors is an integer number (63630639738).

Almost surely, 2212102132455 is an apocalyptic number.

212102132455 is a deficient number, since it is larger than the sum of its proper divisors (42420426497).

212102132455 is an equidigital number, since it uses as much as digits as its factorization.

212102132455 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 42420426496.

The product of its (nonzero) digits is 4800, while the sum is 28.

Adding to 212102132455 its reverse (554231201212), we get a palindrome (766333333667).

The spelling of 212102132455 in words is "two hundred twelve billion, one hundred two million, one hundred thirty-two thousand, four hundred fifty-five".

Divisors: 1 5 42420426491 212102132455