Search a number
-
+
212120010010133 is a prime number
BaseRepresentation
bin110000001110110000001001…
…110110001010111000010101
31000211001110211012201100011222
4300032300021312022320111
5210300333240030311013
62031050330510340125
762452110406513511
oct6016601166127025
91024043735640158
10212120010010133
116165165576a005
121b95a3421ba645
139148aa5c5c184
143a5493ddd3141
15197cadcc91508
hexc0ec09d8ae15

212120010010133 has 2 divisors, whose sum is σ = 212120010010134. Its totient is φ = 212120010010132.

The previous prime is 212120010010123. The next prime is 212120010010231. The reversal of 212120010010133 is 331010010021212.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 205376213888209 + 6743796121924 = 14330953^2 + 2596882^2 .

It is a cyclic number.

It is not a de Polignac number, because 212120010010133 - 216 = 212120009944597 is a prime.

It is a super-3 number, since 3×2121200100101333 (a number of 44 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (212120010010123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106060005005066 + 106060005005067.

It is an arithmetic number, because the mean of its divisors is an integer number (106060005005067).

Almost surely, 2212120010010133 is an apocalyptic number.

It is an amenable number.

212120010010133 is a deficient number, since it is larger than the sum of its proper divisors (1).

212120010010133 is an equidigital number, since it uses as much as digits as its factorization.

212120010010133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 212120010010133 its reverse (331010010021212), we get a palindrome (543130020031345).

The spelling of 212120010010133 in words is "two hundred twelve trillion, one hundred twenty billion, ten million, ten thousand, one hundred thirty-three".