Base | Representation |
---|---|
bin | 11110110111100111111… |
… | …111010001010111010111 |
3 | 21111210110210220011101221 |
4 | 132313213333101113113 |
5 | 234223421104000043 |
6 | 4302303344431211 |
7 | 306155030663665 |
oct | 36674777212727 |
9 | 7453423804357 |
10 | 2121311000023 |
11 | 7487088366a6 |
12 | 2a315a918507 |
13 | 1250672384a7 |
14 | 74959d7bc35 |
15 | 3a2a80e78ed |
hex | 1ede7fd15d7 |
2121311000023 has 2 divisors, whose sum is σ = 2121311000024. Its totient is φ = 2121311000022.
The previous prime is 2121311000009. The next prime is 2121311000089. The reversal of 2121311000023 is 3200001131212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2121311000023 - 25 = 2121310999991 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2121310999970 and 2121311000006.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2121311090023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1060655500011 + 1060655500012.
It is an arithmetic number, because the mean of its divisors is an integer number (1060655500012).
Almost surely, 22121311000023 is an apocalyptic number.
2121311000023 is a deficient number, since it is larger than the sum of its proper divisors (1).
2121311000023 is an equidigital number, since it uses as much as digits as its factorization.
2121311000023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 2121311000023 its reverse (3200001131212), we get a palindrome (5321312131235).
The spelling of 2121311000023 in words is "two trillion, one hundred twenty-one billion, three hundred eleven million, twenty-three", and thus it is an aban number.
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