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212200211141 is a prime number
BaseRepresentation
bin1100010110100000011…
…1100100001011000101
3202021201121010121220022
43011220013210023011
511434041223224031
6241252230544525
721221343014462
oct3055007441305
9667647117808
10212200211141
1181aa253a426
1235161508145
1317019ab3119
14a3b0538669
1557be59197b
hex31681e42c5

212200211141 has 2 divisors, whose sum is σ = 212200211142. Its totient is φ = 212200211140.

The previous prime is 212200211063. The next prime is 212200211143. The reversal of 212200211141 is 141112002212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 142268524225 + 69931686916 = 377185^2 + 264446^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-212200211141 is a prime.

Together with 212200211143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (212200211143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106100105570 + 106100105571.

It is an arithmetic number, because the mean of its divisors is an integer number (106100105571).

Almost surely, 2212200211141 is an apocalyptic number.

It is an amenable number.

212200211141 is a deficient number, since it is larger than the sum of its proper divisors (1).

212200211141 is an equidigital number, since it uses as much as digits as its factorization.

212200211141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 212200211141 its reverse (141112002212), we get a palindrome (353312213353).

The spelling of 212200211141 in words is "two hundred twelve billion, two hundred million, two hundred eleven thousand, one hundred forty-one".