Base | Representation |
---|---|
bin | 10011110001011010… |
… | …111111110011100111 |
3 | 2000210120110201022011 |
4 | 103301122333303213 |
5 | 321434421132320 |
6 | 13430354015051 |
7 | 1351051123102 |
oct | 236132776347 |
9 | 60716421264 |
10 | 21230255335 |
11 | 9004a20073 |
12 | 4145b77487 |
13 | 2004533383 |
14 | 105584d739 |
15 | 843c8105a |
hex | 4f16bfce7 |
21230255335 has 4 divisors (see below), whose sum is σ = 25476306408. Its totient is φ = 16984204264.
The previous prime is 21230255329. The next prime is 21230255369. The reversal of 21230255335 is 53355203212.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 21230255335 - 25 = 21230255303 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 21230255297 and 21230255306.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2123025529 + ... + 2123025538.
It is an arithmetic number, because the mean of its divisors is an integer number (6369076602).
Almost surely, 221230255335 is an apocalyptic number.
21230255335 is a deficient number, since it is larger than the sum of its proper divisors (4246051073).
21230255335 is an equidigital number, since it uses as much as digits as its factorization.
21230255335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4246051072.
The product of its (nonzero) digits is 27000, while the sum is 31.
Adding to 21230255335 its reverse (53355203212), we get a palindrome (74585458547).
The spelling of 21230255335 in words is "twenty-one billion, two hundred thirty million, two hundred fifty-five thousand, three hundred thirty-five".
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