Base | Representation |
---|---|
bin | 11110111011001110000… |
… | …101100001100100100110 |
3 | 21112011102211220202011222 |
4 | 132323032011201210212 |
5 | 234304322334231300 |
6 | 4304142410300342 |
7 | 306352504561235 |
oct | 36731605414446 |
9 | 7464384822158 |
10 | 2125171398950 |
11 | 74a309940536 |
12 | 2a3a577276b2 |
13 | 125530c5c302 |
14 | 74c04952b1c |
15 | 3a431e94785 |
hex | 1eece161926 |
2125171398950 has 24 divisors (see below), whose sum is σ = 3962980326240. Its totient is φ = 847883285600.
The previous prime is 2125171398937. The next prime is 2125171398953. The reversal of 2125171398950 is 598931715212.
It is a super-2 number, since 2×21251713989502 (a number of 25 digits) contains 22 as substring.
It is a hoax number, since the sum of its digits (53) coincides with the sum of the digits of its distinct prime factors.
It is a junction number, because it is equal to n+sod(n) for n = 2125171398892 and 2125171398901.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2125171398953) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 54612206 + ... + 54651105.
It is an arithmetic number, because the mean of its divisors is an integer number (165124180260).
Almost surely, 22125171398950 is an apocalyptic number.
2125171398950 is a deficient number, since it is larger than the sum of its proper divisors (1837808927290).
2125171398950 is a wasteful number, since it uses less digits than its factorization.
2125171398950 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 109263712 (or 109263707 counting only the distinct ones).
The product of its (nonzero) digits is 1360800, while the sum is 53.
The spelling of 2125171398950 in words is "two trillion, one hundred twenty-five billion, one hundred seventy-one million, three hundred ninety-eight thousand, nine hundred fifty".
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