Base | Representation |
---|---|
bin | 1100011001100001100… |
… | …1001000001001101000 |
3 | 202100211001010022210121 |
4 | 3012120121020021220 |
5 | 11442221042340240 |
6 | 241504442053024 |
7 | 21250406104603 |
oct | 3063031101150 |
9 | 670731108717 |
10 | 213010121320 |
11 | 82378729987 |
12 | 353487aa174 |
13 | 17118825a09 |
14 | a449d2333a |
15 | 581a72504a |
hex | 3198648268 |
213010121320 has 16 divisors (see below), whose sum is σ = 479272773060. Its totient is φ = 85204048512.
The previous prime is 213010121309. The next prime is 213010121341. The reversal of 213010121320 is 23121010312.
It can be written as a sum of positive squares in 2 ways, for example, as 202397412996 + 10612708324 = 449886^2 + 103018^2 .
It is a super-2 number, since 2×2130101213202 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 213010121294 and 213010121303.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2662626477 + ... + 2662626556.
Almost surely, 2213010121320 is an apocalyptic number.
213010121320 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
213010121320 is an abundant number, since it is smaller than the sum of its proper divisors (266262651740).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
213010121320 is a wasteful number, since it uses less digits than its factorization.
213010121320 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5325253044 (or 5325253040 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 213010121320 its reverse (23121010312), we get a palindrome (236131131632).
The spelling of 213010121320 in words is "two hundred thirteen billion, ten million, one hundred twenty-one thousand, three hundred twenty".
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