Base | Representation |
---|---|
bin | 1001101011111100001110… |
… | …10100000011101011111000 |
3 | 2210102100122012221211202112 |
4 | 10311332013110003223320 |
5 | 10242443433312044000 |
6 | 113145314505551452 |
7 | 4325642650051643 |
oct | 465760724035370 |
9 | 83370565854675 |
10 | 21301013003000 |
11 | 6872788584395 |
12 | 24803421a5588 |
13 | bb68a521ba23 |
14 | 538d9017aa5a |
15 | 26e14cbaa235 |
hex | 135f87503af8 |
21301013003000 has 64 divisors (see below), whose sum is σ = 49852514668320. Its totient is φ = 8519013024000.
The previous prime is 21301013002987. The next prime is 21301013003009. The reversal of 21301013003000 is 30031010312.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21301013003009) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4393844 + ... + 7868156.
Almost surely, 221301013003000 is an apocalyptic number.
21301013003000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
21301013003000 is an abundant number, since it is smaller than the sum of its proper divisors (28551501665320).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
21301013003000 is a wasteful number, since it uses less digits than its factorization.
21301013003000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3480465 (or 3480451 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 21301013003000 its reverse (30031010312), we get a palindrome (21331044013312).
The spelling of 21301013003000 in words is "twenty-one trillion, three hundred one billion, thirteen million, three thousand".
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