Base | Representation |
---|---|
bin | 110000011100001001011101… |
… | …001111101101001100010000 |
3 | 1000221022110211222122102110011 |
4 | 300130021131033231030100 |
5 | 210410424002221331134 |
6 | 2033033245220044304 |
7 | 62605445663245006 |
oct | 6034113517551420 |
9 | 1027273758572404 |
10 | 213040532214544 |
11 | 61976a89530811 |
12 | 1ba88823233694 |
13 | 91b48363508a8 |
14 | 3a87306b96a76 |
15 | 1996a16cdb264 |
hex | c1c25d3ed310 |
213040532214544 has 80 divisors (see below), whose sum is σ = 417900621219840. Its totient is φ = 105200607680000.
The previous prime is 213040532214493. The next prime is 213040532214563. The reversal of 213040532214544 is 445412235040312.
It is a super-3 number, since 3×2130405322145443 (a number of 44 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 213040532214497 and 213040532214506.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3998556897 + ... + 3998610175.
It is an arithmetic number, because the mean of its divisors is an integer number (5223757765248).
Almost surely, 2213040532214544 is an apocalyptic number.
It is an amenable number.
213040532214544 is a deficient number, since it is larger than the sum of its proper divisors (204860089005296).
213040532214544 is a wasteful number, since it uses less digits than its factorization.
213040532214544 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 59560 (or 59554 counting only the distinct ones).
The product of its (nonzero) digits is 460800, while the sum is 40.
Adding to 213040532214544 its reverse (445412235040312), we get a palindrome (658452767254856).
The spelling of 213040532214544 in words is "two hundred thirteen trillion, forty billion, five hundred thirty-two million, two hundred fourteen thousand, five hundred forty-four".
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