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213100310231 is a prime number
BaseRepresentation
bin1100011001110111000…
…1001010111011010111
3202101001022211101201122
43012131301022323113
511442412134411411
6241521423114155
721252552515204
oct3063561127327
9671038741648
10213100310231
118241462a176
1235372a4295b
1317131412933
14a457cbccab
1558235dc9db
hex319dc4aed7

213100310231 has 2 divisors, whose sum is σ = 213100310232. Its totient is φ = 213100310230.

The previous prime is 213100310221. The next prime is 213100310233. The reversal of 213100310231 is 132013001312.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 213100310231 - 210 = 213100309207 is a prime.

It is a super-2 number, since 2×2131003102312 (a number of 23 digits) contains 22 as substring.

Together with 213100310233, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (213100310233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106550155115 + 106550155116.

It is an arithmetic number, because the mean of its divisors is an integer number (106550155116).

Almost surely, 2213100310231 is an apocalyptic number.

213100310231 is a deficient number, since it is larger than the sum of its proper divisors (1).

213100310231 is an equidigital number, since it uses as much as digits as its factorization.

213100310231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 213100310231 its reverse (132013001312), we get a palindrome (345113311543).

The spelling of 213100310231 in words is "two hundred thirteen billion, one hundred million, three hundred ten thousand, two hundred thirty-one".