2131234031 has 2 divisors, whose sum is σ = 2131234032. Its totient is φ = 2131234030.

The previous prime is 2131234013. The next prime is 2131234033. The reversal of 2131234031 is 1304321312.

Together with previous prime (2131234013) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2131234031 - 2³⁰ = 1057492207 is a prime.

It is a super-2 number, since 2×2131234031² = 9084316989785017922, which contains 22 as substring.

Together with 2131234033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 2131233994 and 2131234012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2131234033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065617015 + 1065617016.

It is an arithmetic number, because the mean of its divisors is an integer number (1065617016).

Almost surely, 2^2131234031 is an apocalyptic number.

2131234031 is a deficient number, since it is larger than the sum of its proper divisors (1).

2131234031 is an equidigital number, since it uses as much as digits as its factorization.

2131234031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 20.

The square root of 2131234031 is about 46165.2903272578. The cubic root of 2131234031 is about 1286.8967796154.

Adding to 2131234031 its reverse (1304321312), we get a palindrome (3435555343).

The spelling of 2131234031 in words is "two billion, one hundred thirty-one million, two hundred thirty-four thousand, thirty-one".