Base | Representation |
---|---|
bin | 110000011101011101101110… |
… | …110011100000001101010011 |
3 | 1000221122010102022111022212020 |
4 | 300131131232303200031103 |
5 | 210413414312401440220 |
6 | 2033143012303302523 |
7 | 62615131250265561 |
oct | 6035355663401523 |
9 | 1027563368438766 |
10 | 213131021124435 |
11 | 61a013a4124067 |
12 | 1baa22778aaa43 |
13 | 91c022754415b |
14 | 3a8b84c9a0a31 |
15 | 1999061040040 |
hex | c1d76ece0353 |
213131021124435 has 64 divisors (see below), whose sum is σ = 369713806617600. Its totient is φ = 104520055546368.
The previous prime is 213131021124433. The next prime is 213131021124449. The reversal of 213131021124435 is 534421120131312.
It is not a de Polignac number, because 213131021124435 - 21 = 213131021124433 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 213131021124396 and 213131021124405.
It is not an unprimeable number, because it can be changed into a prime (213131021124433) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 44220757 + ... + 48803046.
It is an arithmetic number, because the mean of its divisors is an integer number (5776778228400).
Almost surely, 2213131021124435 is an apocalyptic number.
213131021124435 is a deficient number, since it is larger than the sum of its proper divisors (156582785493165).
213131021124435 is a wasteful number, since it uses less digits than its factorization.
213131021124435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 93024092.
The product of its (nonzero) digits is 17280, while the sum is 33.
Adding to 213131021124435 its reverse (534421120131312), we get a palindrome (747552141255747).
The spelling of 213131021124435 in words is "two hundred thirteen trillion, one hundred thirty-one billion, twenty-one million, one hundred twenty-four thousand, four hundred thirty-five".
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