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2131311210132 = 2231313662251347
BaseRepresentation
bin11111000000111100000…
…011000010111010010100
321112202021202001110202010
4133000330003002322110
5234404411132211012
64311035535544220
7306660610242336
oct37007403027224
97482252043663
102131311210132
1175197a684555
122a508b98b070
13125c9bc9a490
1475228157456
153a690ee7c3c
hex1f03c0c2e94

2131311210132 has 24 divisors (see below), whose sum is σ = 5355602528416. Its totient is φ = 655788064608.

The previous prime is 2131311210131. The next prime is 2131311210137. The reversal of 2131311210132 is 2310121131312.

It is a junction number, because it is equal to n+sod(n) for n = 2131311210099 and 2131311210108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2131311210131) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6831125518 + ... + 6831125829.

Almost surely, 22131311210132 is an apocalyptic number.

It is an amenable number.

2131311210132 is an abundant number, since it is smaller than the sum of its proper divisors (3224291318284).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2131311210132 is a wasteful number, since it uses less digits than its factorization.

2131311210132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13662251367 (or 13662251365 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 2131311210132 its reverse (2310121131312), we get a palindrome (4441432341444).

The spelling of 2131311210132 in words is "two trillion, one hundred thirty-one billion, three hundred eleven million, two hundred ten thousand, one hundred thirty-two".

Divisors: 1 2 3 4 6 12 13 26 39 52 78 156 13662251347 27324502694 40986754041 54649005388 81973508082 163947016164 177609267511 355218535022 532827802533 710437070044 1065655605066 2131311210132