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2131330100101 is a prime number
BaseRepresentation
bin11111000000111101001…
…011000110101110000101
321112202100001121011220121
4133000331023012232011
5234404431001200401
64311041452501541
7306661226636206
oct37007513065605
97482301534817
102131330100101
1175198a3068a4
122a509617a8b1
13125ca2b82587
147522a8735ad
153a6929c9ca1
hex1f03d2c6b85

2131330100101 has 2 divisors, whose sum is σ = 2131330100102. Its totient is φ = 2131330100100.

The previous prime is 2131330100099. The next prime is 2131330100117. The reversal of 2131330100101 is 1010010331312.

It is an a-pointer prime, because the next prime (2131330100117) can be obtained adding 2131330100101 to its sum of digits (16).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2126041029025 + 5289071076 = 1458095^2 + 72726^2 .

It is a cyclic number.

It is not a de Polignac number, because 2131330100101 - 21 = 2131330100099 is a prime.

Together with 2131330100099, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2131330110101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065665050050 + 1065665050051.

It is an arithmetic number, because the mean of its divisors is an integer number (1065665050051).

Almost surely, 22131330100101 is an apocalyptic number.

It is an amenable number.

2131330100101 is a deficient number, since it is larger than the sum of its proper divisors (1).

2131330100101 is an equidigital number, since it uses as much as digits as its factorization.

2131330100101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 2131330100101 its reverse (1010010331312), we get a palindrome (3141340431413).

The spelling of 2131330100101 in words is "two trillion, one hundred thirty-one billion, three hundred thirty million, one hundred thousand, one hundred one".