Base | Representation |
---|---|
bin | 111111100001011… |
… | …0001101010001101 |
3 | 12111112200001221122 |
4 | 1333002301222031 |
5 | 13331121343000 |
6 | 551300010325 |
7 | 103550614442 |
oct | 17702615215 |
9 | 5445601848 |
10 | 2131434125 |
11 | 9a4159007 |
12 | 4b59909a5 |
13 | 27c775832 |
14 | 16310d9c9 |
15 | c71c6085 |
hex | 7f0b1a8d |
2131434125 has 16 divisors (see below), whose sum is σ = 2671105008. Its totient is φ = 1698048000.
The previous prime is 2131434119. The next prime is 2131434163. The reversal of 2131434125 is 5214341312.
It is a happy number.
It can be written as a sum of positive squares in 8 ways, for example, as 723233449 + 1408200676 = 26893^2 + 37526^2 .
It is not a de Polignac number, because 2131434125 - 226 = 2064325261 is a prime.
It is a super-2 number, since 2×21314341252 = 9086022858429031250, which contains 22 as substring.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 2131434094 and 2131434103.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5252 + ... + 65501.
It is an arithmetic number, because the mean of its divisors is an integer number (166944063).
Almost surely, 22131434125 is an apocalyptic number.
2131434125 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
It is an amenable number.
2131434125 is a deficient number, since it is larger than the sum of its proper divisors (539670883).
2131434125 is an equidigital number, since it uses as much as digits as its factorization.
2131434125 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 71009 (or 70999 counting only the distinct ones).
The product of its digits is 2880, while the sum is 26.
The square root of 2131434125 is about 46167.4574240341. The cubic root of 2131434125 is about 1286.9370524123.
Adding to 2131434125 its reverse (5214341312), we get a palindrome (7345775437).
The spelling of 2131434125 in words is "two billion, one hundred thirty-one million, four hundred thirty-four thousand, one hundred twenty-five".
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