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213201101 is a prime number
BaseRepresentation
bin11001011010100…
…11000011001101
3112212011201221002
430231103003031
5414034413401
633053350045
75166115361
oct1455230315
9485151832
10213201101
11aa38a163
125b498325
1335229bc9
142045b2a1
1513ab5a6b
hexcb530cd

213201101 has 2 divisors, whose sum is σ = 213201102. Its totient is φ = 213201100.

The previous prime is 213201091. The next prime is 213201103. The reversal of 213201101 is 101102312.

213201101 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 136656100 + 76545001 = 11690^2 + 8749^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-213201101 is a prime.

It is a super-2 number, since 2×2132011012 = 90909418935224402, which contains 22 as substring.

Together with 213201103, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (213201103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106600550 + 106600551.

It is an arithmetic number, because the mean of its divisors is an integer number (106600551).

Almost surely, 2213201101 is an apocalyptic number.

It is an amenable number.

213201101 is a deficient number, since it is larger than the sum of its proper divisors (1).

213201101 is an equidigital number, since it uses as much as digits as its factorization.

213201101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 213201101 is about 14601.4075006487. The cubic root of 213201101 is about 597.3971518150.

Adding to 213201101 its reverse (101102312), we get a palindrome (314303413).

The spelling of 213201101 in words is "two hundred thirteen million, two hundred one thousand, one hundred one".