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213220115 = 542644023
BaseRepresentation
bin11001011010101…
…11101100010011
3112212012201000022
430231113230103
5414041020430
633054014055
75166224663
oct1455275423
9485181008
10213220115
11aa3a2479
125b4a732b
1335235764
14204641a3
1513abb4e5
hexcb57b13

213220115 has 4 divisors (see below), whose sum is σ = 255864144. Its totient is φ = 170576088.

The previous prime is 213220099. The next prime is 213220127. The reversal of 213220115 is 511022312.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 213220115 - 24 = 213220099 is a prime.

It is a super-2 number, since 2×2132201152 = 90925634881226450, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 213220093 and 213220102.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21322007 + ... + 21322016.

It is an arithmetic number, because the mean of its divisors is an integer number (63966036).

Almost surely, 2213220115 is an apocalyptic number.

213220115 is a deficient number, since it is larger than the sum of its proper divisors (42644029).

213220115 is an equidigital number, since it uses as much as digits as its factorization.

213220115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 42644028.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 213220115 is about 14602.0585877471. The cubic root of 213220115 is about 597.4149105910.

Adding to 213220115 its reverse (511022312), we get a palindrome (724242427).

The spelling of 213220115 in words is "two hundred thirteen million, two hundred twenty thousand, one hundred fifteen".

Divisors: 1 5 42644023 213220115