Base | Representation |
---|---|
bin | 10011110111011100… |
… | …111101011010001100 |
3 | 2001001121212002002210 |
4 | 103313130331122030 |
5 | 322141321324400 |
6 | 13444410350420 |
7 | 1353420122025 |
oct | 236734753214 |
9 | 61047762083 |
10 | 21331433100 |
11 | 905704645a |
12 | 4173a2b410 |
13 | 201c499c83 |
14 | 1065069c4c |
15 | 84cab9950 |
hex | 4f773d68c |
21331433100 has 36 divisors (see below), whose sum is σ = 61718947304. Its totient is φ = 5688382080.
The previous prime is 21331433093. The next prime is 21331433131. The reversal of 21331433100 is 133413312.
It is a super-2 number, since 2×213314331002 (a number of 21 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 35552089 + ... + 35552688.
Almost surely, 221331433100 is an apocalyptic number.
21331433100 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
21331433100 is an abundant number, since it is smaller than the sum of its proper divisors (40387514204).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
21331433100 is a wasteful number, since it uses less digits than its factorization.
21331433100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 71104794 (or 71104787 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 21331433100 its reverse (133413312), we get a palindrome (21464846412).
The spelling of 21331433100 in words is "twenty-one billion, three hundred thirty-one million, four hundred thirty-three thousand, one hundred".
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