Search a number
-
+
213333130110100 = 22527111347331136993
BaseRepresentation
bin110000100000011001111101…
…011100000110010010010100
31000222100110002122012120210211
4300200121331130012102110
5210430222222302010400
62033415515332255204
762635544560313050
oct6040317534062224
91028313078176724
10213333130110100
1161a7a088400420
121bb15481771504
1392062c6779130
143a97542bcac60
15199e43e703dba
hexc2067d706494

213333130110100 has 576 divisors, whose sum is σ = 636707360120832. Its totient is φ = 59890710528000.

The previous prime is 213333130110097. The next prime is 213333130110251. The reversal of 213333130110100 is 1011031333312.

It is a super-2 number, since 2×2133331301101002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (22).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 1557187204 + ... + 1557324196.

It is an arithmetic number, because the mean of its divisors is an integer number (1105394722432).

Almost surely, 2213333130110100 is an apocalyptic number.

213333130110100 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 213333130110100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (318353680060416).

213333130110100 is an abundant number, since it is smaller than the sum of its proper divisors (423374230010732).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

213333130110100 is a wasteful number, since it uses less digits than its factorization.

213333130110100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 137416 (or 137409 counting only the distinct ones).

The product of its (nonzero) digits is 486, while the sum is 22.

Adding to 213333130110100 its reverse (1011031333312), we get a palindrome (214344161443412).

The spelling of 213333130110100 in words is "two hundred thirteen trillion, three hundred thirty-three billion, one hundred thirty million, one hundred ten thousand, one hundred".