Base | Representation |
---|---|
bin | 10011111000000010… |
… | …110000111001101101 |
3 | 2001002022111120101202 |
4 | 103320002300321231 |
5 | 322201340441331 |
6 | 13445403015245 |
7 | 1353600265613 |
oct | 237002607155 |
9 | 61068446352 |
10 | 21341343341 |
11 | 90616a513a |
12 | 417720a525 |
13 | 2021559a16 |
14 | 10664c96b3 |
15 | 84d8c5ecb |
hex | 4f80b0e6d |
21341343341 has 2 divisors, whose sum is σ = 21341343342. Its totient is φ = 21341343340.
The previous prime is 21341343319. The next prime is 21341343379. The reversal of 21341343341 is 14334314312.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 15931740841 + 5409602500 = 126221^2 + 73550^2 .
It is a cyclic number.
It is not a de Polignac number, because 21341343341 - 218 = 21341081197 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21341343301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10670671670 + 10670671671.
It is an arithmetic number, because the mean of its divisors is an integer number (10670671671).
Almost surely, 221341343341 is an apocalyptic number.
It is an amenable number.
21341343341 is a deficient number, since it is larger than the sum of its proper divisors (1).
21341343341 is an equidigital number, since it uses as much as digits as its factorization.
21341343341 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 10368, while the sum is 29.
Adding to 21341343341 its reverse (14334314312), we get a palindrome (35675657653).
The spelling of 21341343341 in words is "twenty-one billion, three hundred forty-one million, three hundred forty-three thousand, three hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •