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213425614151 is a prime number
BaseRepresentation
bin1100011011000100101…
…0000110110101000111
3202101212222221112210222
43012301022012311013
511444043424123101
6242014003334555
721263612534141
oct3066112066507
9671788845728
10213425614151
1182571216892
123544398145b
1317183930069
14a48919bc91
155841e4901b
hex31b1286d47

213425614151 has 2 divisors, whose sum is σ = 213425614152. Its totient is φ = 213425614150.

The previous prime is 213425614097. The next prime is 213425614153. The reversal of 213425614151 is 151416524312.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-213425614151 is a prime.

Together with 213425614153, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (213425614153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106712807075 + 106712807076.

It is an arithmetic number, because the mean of its divisors is an integer number (106712807076).

Almost surely, 2213425614151 is an apocalyptic number.

213425614151 is a deficient number, since it is larger than the sum of its proper divisors (1).

213425614151 is an equidigital number, since it uses as much as digits as its factorization.

213425614151 is an evil number, because the sum of its binary digits is even.

The product of its digits is 28800, while the sum is 35.

The spelling of 213425614151 in words is "two hundred thirteen billion, four hundred twenty-five million, six hundred fourteen thousand, one hundred fifty-one".