Base | Representation |
---|---|
bin | 1100011011000110111… |
… | …1011100010011101111 |
3 | 202101220200100210110201 |
4 | 3012301233130103233 |
5 | 11444103430321310 |
6 | 242014553214331 |
7 | 21264061656433 |
oct | 3066157342357 |
9 | 671820323421 |
10 | 213435401455 |
11 | 825767a1171 |
12 | 354471013a7 |
13 | 17185978b73 |
14 | a48a5c89c3 |
15 | 5842c2de3a |
hex | 31b1bdc4ef |
213435401455 has 16 divisors (see below), whose sum is σ = 272167560000. Its totient is φ = 160124124672.
The previous prime is 213435401371. The next prime is 213435401461. The reversal of 213435401455 is 554104534312.
It is a cyclic number.
It is not a de Polignac number, because 213435401455 - 215 = 213435368687 is a prime.
It is a super-2 number, since 2×2134354014552 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4508955 + ... + 4556044.
It is an arithmetic number, because the mean of its divisors is an integer number (17010472500).
Almost surely, 2213435401455 is an apocalyptic number.
213435401455 is a deficient number, since it is larger than the sum of its proper divisors (58732158545).
213435401455 is a wasteful number, since it uses less digits than its factorization.
213435401455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9065298.
The product of its (nonzero) digits is 144000, while the sum is 37.
Adding to 213435401455 its reverse (554104534312), we get a palindrome (767539935767).
The spelling of 213435401455 in words is "two hundred thirteen billion, four hundred thirty-five million, four hundred one thousand, four hundred fifty-five".
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