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213512210243149 is a prime number
BaseRepresentation
bin110000100011000000101111…
…011100100101111001001101
31000222222120100001001220211011
4300203000233130211321031
5210441141001310240044
62034034053313125221
762654514416321236
oct6043005734457115
91028876301056734
10213512210243149
1162039024480984
121bb4411b259811
13921a16595c2bc
143aa209077808d
1519a3e212a9134
hexc2302f725e4d

213512210243149 has 2 divisors, whose sum is σ = 213512210243150. Its totient is φ = 213512210243148.

The previous prime is 213512210243063. The next prime is 213512210243173. The reversal of 213512210243149 is 941342012215312.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 212451759275625 + 1060450967524 = 14575725^2 + 1029782^2 .

It is a cyclic number.

It is not a de Polignac number, because 213512210243149 - 211 = 213512210241101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (213512210213149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106756105121574 + 106756105121575.

It is an arithmetic number, because the mean of its divisors is an integer number (106756105121575).

Almost surely, 2213512210243149 is an apocalyptic number.

It is an amenable number.

213512210243149 is a deficient number, since it is larger than the sum of its proper divisors (1).

213512210243149 is an equidigital number, since it uses as much as digits as its factorization.

213512210243149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 103680, while the sum is 40.

The spelling of 213512210243149 in words is "two hundred thirteen trillion, five hundred twelve billion, two hundred ten million, two hundred forty-three thousand, one hundred forty-nine".