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21414031212130 = 252393104483531
BaseRepresentation
bin1001101111001110101111…
…01110010011111001100010
32210211011100122122201200221
410313213113232103321202
510301321413442242010
6113313245314233254
74340053441014634
oct467472756237142
983734318581627
1021414031212130
1169067043a1707
12249a22388582a
13bc4446b0739b
14540632146a54
15272064c41dda
hex1379d7b93e62

21414031212130 has 16 divisors (see below), whose sum is σ = 40221136885824. Its totient is φ = 8193194550640.

The previous prime is 21414031212073. The next prime is 21414031212149. The reversal of 21414031212130 is 3121213041412.

It is a junction number, because it is equal to n+sod(n) for n = 21414031212095 and 21414031212104.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 46552241536 + ... + 46552241995.

It is an arithmetic number, because the mean of its divisors is an integer number (2513821055364).

Almost surely, 221414031212130 is an apocalyptic number.

21414031212130 is a deficient number, since it is larger than the sum of its proper divisors (18807105673694).

21414031212130 is a wasteful number, since it uses less digits than its factorization.

21414031212130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 93104483561.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 21414031212130 its reverse (3121213041412), we get a palindrome (24535244253542).

It can be divided in two parts, 2141403 and 1212130, that added together give a palindrome (3353533).

The spelling of 21414031212130 in words is "twenty-one trillion, four hundred fourteen billion, thirty-one million, two hundred twelve thousand, one hundred thirty".

Divisors: 1 2 5 10 23 46 115 230 93104483531 186208967062 465522417655 931044835310 2141403121213 4282806242426 10707015606065 21414031212130