Base | Representation |
---|---|
bin | 11111001010010101101… |
… | …000010111110101111111 |
3 | 21120201100010121111120121 |
4 | 133022111220113311333 |
5 | 240041043422231030 |
6 | 4315425241355411 |
7 | 310465663353163 |
oct | 37122550276577 |
9 | 7521303544517 |
10 | 2141404102015 |
11 | 756189875612 |
12 | 2a7027a98b67 |
13 | 126c19cacc59 |
14 | 7590477aca3 |
15 | 3aa8210447a |
hex | 1f295a17d7f |
2141404102015 has 8 divisors (see below), whose sum is σ = 2570487216048. Its totient is φ = 1712588419200.
The previous prime is 2141404102003. The next prime is 2141404102031. The reversal of 2141404102015 is 5102014041412.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2141404102015 - 213 = 2141404093823 is a prime.
It is a super-2 number, since 2×21414041020152 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 66840186 + ... + 66872215.
It is an arithmetic number, because the mean of its divisors is an integer number (321310902006).
Almost surely, 22141404102015 is an apocalyptic number.
2141404102015 is a deficient number, since it is larger than the sum of its proper divisors (429083114033).
2141404102015 is a wasteful number, since it uses less digits than its factorization.
2141404102015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 133715609.
The product of its (nonzero) digits is 1280, while the sum is 25.
Adding to 2141404102015 its reverse (5102014041412), we get a palindrome (7243418143427).
The spelling of 2141404102015 in words is "two trillion, one hundred forty-one billion, four hundred four million, one hundred two thousand, fifteen".
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