Base | Representation |
---|---|
bin | 11111001100001110011… |
… | …101111110110011001011 |
3 | 21120220120102100222120210 |
4 | 133030032131332303023 |
5 | 240104221420434011 |
6 | 4320402342052203 |
7 | 310600141316430 |
oct | 37141635766313 |
9 | 7526512328523 |
10 | 2143431421131 |
11 | 75702a181460 |
12 | 2a74b2a1a063 |
13 | 127181000c70 |
14 | 75a57b07b87 |
15 | 3ab500b16a6 |
hex | 1f30e77eccb |
2143431421131 has 128 divisors (see below), whose sum is σ = 4064497920000. Its totient is φ = 966981058560.
The previous prime is 2143431421069. The next prime is 2143431421133. The reversal of 2143431421131 is 1311241343412.
It is not a de Polignac number, because 2143431421131 - 211 = 2143431419083 is a prime.
It is a super-2 number, since 2×21434314211312 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (2143431421133) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 161773995 + ... + 161787243.
It is an arithmetic number, because the mean of its divisors is an integer number (31753890000).
Almost surely, 22143431421131 is an apocalyptic number.
2143431421131 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
2143431421131 is a deficient number, since it is larger than the sum of its proper divisors (1921066498869).
2143431421131 is a wasteful number, since it uses less digits than its factorization.
2143431421131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16469.
The product of its digits is 6912, while the sum is 30.
Adding to 2143431421131 its reverse (1311241343412), we get a palindrome (3454672764543).
The spelling of 2143431421131 in words is "two trillion, one hundred forty-three billion, four hundred thirty-one million, four hundred twenty-one thousand, one hundred thirty-one".
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