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214551004135 = 5133300784679
BaseRepresentation
bin1100011111010000111…
…1001000001111100111
3202111210102120021122111
43013310033020033213
512003400024113020
6242321404341451
721333526305406
oct3076417101747
9674712507574
10214551004135
1182a994a2a56
12356b8844887
1317302b305b0
14a55482963d
1558aab47d5a
hex31f43c83e7

214551004135 has 8 divisors (see below), whose sum is σ = 277265913120. Its totient is φ = 158437664544.

The previous prime is 214551004069. The next prime is 214551004139. The reversal of 214551004135 is 531400155412.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 214551004135 - 215 = 214550971367 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 214551004097 and 214551004106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (214551004139) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1650392275 + ... + 1650392404.

It is an arithmetic number, because the mean of its divisors is an integer number (34658239140).

Almost surely, 2214551004135 is an apocalyptic number.

214551004135 is a deficient number, since it is larger than the sum of its proper divisors (62714908985).

214551004135 is a wasteful number, since it uses less digits than its factorization.

214551004135 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3300784697.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 214551004135 its reverse (531400155412), we get a palindrome (745951159547).

The spelling of 214551004135 in words is "two hundred fourteen billion, five hundred fifty-one million, four thousand, one hundred thirty-five".

Divisors: 1 5 13 65 3300784679 16503923395 42910200827 214551004135