Base | Representation |
---|---|
bin | 11111010011011111100… |
… | …111001010111001110111 |
3 | 21121122201021121211022122 |
4 | 133103133213022321313 |
5 | 240221212210013242 |
6 | 4324132552550155 |
7 | 311264420536604 |
oct | 37233747127167 |
9 | 7548637554278 |
10 | 2151235235447 |
11 | 75a374231681 |
12 | 2a8b103b235b |
13 | 127b259c3c7c |
14 | 761983036ab |
15 | 3ae5a257ad2 |
hex | 1f4df9cae77 |
2151235235447 has 2 divisors, whose sum is σ = 2151235235448. Its totient is φ = 2151235235446.
The previous prime is 2151235235423. The next prime is 2151235235449. The reversal of 2151235235447 is 7445325321512.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2151235235447 - 224 = 2151218458231 is a prime.
Together with 2151235235449, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 2151235235398 and 2151235235407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2151235235449) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1075617617723 + 1075617617724.
It is an arithmetic number, because the mean of its divisors is an integer number (1075617617724).
Almost surely, 22151235235447 is an apocalyptic number.
2151235235447 is a deficient number, since it is larger than the sum of its proper divisors (1).
2151235235447 is an equidigital number, since it uses as much as digits as its factorization.
2151235235447 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1008000, while the sum is 44.
The spelling of 2151235235447 in words is "two trillion, one hundred fifty-one billion, two hundred thirty-five million, two hundred thirty-five thousand, four hundred forty-seven".
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