Base | Representation |
---|---|
bin | 110000111010101100110001… |
… | …000110010010010100110101 |
3 | 1001012202012000122011200202022 |
4 | 300322230301012102110311 |
5 | 211144323240310233240 |
6 | 2041321544323522525 |
7 | 63213232341554432 |
oct | 6072546106222465 |
9 | 1035665018150668 |
10 | 215140030555445 |
11 | 626064136177a6 |
12 | 201676b4b29445 |
13 | 93078054ab398 |
14 | 3b1ab93bdcb89 |
15 | 19d1444e5d9b5 |
hex | c3ab31192535 |
215140030555445 has 32 divisors (see below), whose sum is σ = 264843160807680. Its totient is φ = 167719051008000.
The previous prime is 215140030555433. The next prime is 215140030555451. The reversal of 215140030555445 is 544555030041512.
It is a happy number.
It is not a de Polignac number, because 215140030555445 - 212 = 215140030551349 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 215140030555396 and 215140030555405.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 10128005 + ... + 23083685.
It is an arithmetic number, because the mean of its divisors is an integer number (8276348775240).
Almost surely, 2215140030555445 is an apocalyptic number.
It is an amenable number.
215140030555445 is a deficient number, since it is larger than the sum of its proper divisors (49703130252235).
215140030555445 is a wasteful number, since it uses less digits than its factorization.
215140030555445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12956237.
The product of its (nonzero) digits is 1200000, while the sum is 44.
Adding to 215140030555445 its reverse (544555030041512), we get a palindrome (759695060596957).
The spelling of 215140030555445 in words is "two hundred fifteen trillion, one hundred forty billion, thirty million, five hundred fifty-five thousand, four hundred forty-five".
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